Enthalpy
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Overview
Thermodynamics is the study of the transfer of energy. The internal energy of chemical system plus the product of its pressure and volume is known as enthalpy. In this lesson we will explore the change in enthalpy for one of the simplest combustion reactions, the combustion of carbon monoxide to form carbon dioxide.
Figure 1: Combustion reaction of carbon monoxide plus oxygen to form carbon dioxide.
Consider the unbalanced chemical reaction
CO (g) + O2 g → CO2 (g)
(a) Balance the chemical reaction for the combustion of carbon monoxide.
The enthalpy change of the reaction ΔH at standard temperature and pressure (298 K and 1 atm) can be computed from the enthalpies of the reactants and the products, which can be computed from quantum theory. We will compute these enthalpies using the Thermodynamics command in the Quantum Chemistry package. First, we set the Digits to 15 and load the Quantum Chemistry package
Digits ≔ 15:withQuantumChemistry;
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The enthalpies of O2 and CO2 have been precomputed in Table 1.
Table 1: Enthalpies in kJ/mol for the combustion of CO
CO
O2
CO2
H
?
-3.945 x 105 kJ/mol
-4.949 x 105 kJ/mol
The enthalpy of CO can be computed as follows. First, choose an initial guess for the equilibrium bond distance, i.e. 1.1 angstroms and define the geometry.
mol_CO ≔ C,0,0,0,O,0,0,1.1;
mol_CO≔C,0,0,0,O,0,0,1.10000000
Second, optimize the geometry of CO to find the minimum of the potential energy curve using the method density functional theory (DFT) with the default functional (B3-LYP) and the basis set cc-pVDZ.
mol_CO,data_CO ≔ GeometryOptimizationmol_CO, 'DensityFunctional', basis=cc-pvdz: mol_CO;
C,0,0,0,O,7.46697480⁢10−12,1.43245335⁢10−11,1.13485718
(b) At what bond distance of CO does the minimum of the potential energy curve occur? Is this distance shorter or longer than the initial guess of 1.1 angstroms?
Finally, we compute a table of thermodynamic properties for CO including the enthalpy. By default, the command uses a temperature of 298 K.
thermo_CO ≔ Thermodynamicsmol_CO, 'DensityFunctional', basis=cc-pvdz;
thermo_CO≔table⁡entropy=389.04949897⁢Jmol⁢K,enthalpy=−2.97353168⁢108⁢Jmol,electronic_energy=−2.97388047⁢108⁢Jmol,θB=2.74504846⁢K,heat_capacity=20.81001215⁢Jmol⁢K,zpe=13100.56169779⁢Jmol,θC=2.74504846⁢K,free_energy=−2.97469163⁢108⁢Jmol,energy=−2.97355647⁢108⁢Jmol
(c) What is the computed enthalpy of CO in kJ/mol?
We can convert the enthalpy from J/mol to kJ/mol using Maple's convert command
HCO ≔ convertthermo_COenthalpy,'units','kJmol';
HCO≔−297353.16764574⁢kJmol
(d) Using the enthalpy of CO in (c) and the precomputed enthalpy values in Table 1, calculate the change in enthalpy in the combustion of 1 mol of CO.
The precomputed values in Table 1 are as follows
HO2 ≔ −3.945⋅105⋅UnitUnits'kJmol';HCO2 ≔ −4.949⋅105⋅UnitUnits'kJmol';
HO2≔−394500.00000000⁢kJmol
HCO2≔−494900.00000000⁢kJmol
Therefore, we can compute the change in enthalpy from
DeltaH ≔ HCO2−12⋅ HO2−HCO;
DeltaH≔−296.83235426⁢kJmol
(e) Is the reaction exothermic or endothermic?
(f) Compute the change in the enthalpy of the reaction in kJ/mol using enthalpies of formation at standard temperature and pressure (STP).
(g) Does your result in (f) agree with the quantum calculation in (d)?
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