Student[Basics]
CurveSketchSteps
show steps in the plotting of a specified expression
Calling Sequence
Parameters
Description
Examples
Compatibility
CurveSketchSteps(ex, opts)
ex
-
expression or string
opts
options of the form keyword=value where keyword is one of displaystyle, output
The CurveSketchSteps command is used to show how a student might plot a basic expression.
This command handles linear and quadratic polynomials in one variable, as well as single trig, log, 1/x and exponentials that are shifted and scaled. It does not support combinations of these functions and works best when the input is already simplified.
To avoid automatic simplifications the input expression can be given as a string. For example, calling CurveSketchSteps(cos(x-Pi/2)) will first evaluate cos(x-Pi/2) to sin(x) using normal Maple evaluation rules. Instead, call CurveSketchSteps("cos(x-Pi/2"), to internally make use of InertForm:-Parse and avoid this simplification.
The displaystyle and output options can be used to change the output format. See OutputStepsRecord for details.
This function is part of the Student:-Basics package.
with⁡Student:-Basics:
CurveSketchSteps⁡2⁢sin⁡3⁢x+π3+1
Let's plot2⁢sin⁡3⁢x+π3+1•Compared to the plot ofsin⁡x, we have a vertical stretch by a factor of22⋅sin⁡3⋅x+π9+1•Then, we have a horizontal compression by a factor of132⋅sin⁡3⋅x+π9+1•Then, we have a vertical shift of12⋅sin⁡3⋅x+π9+1•Then, we have a horizontal shift of−π92⋅sin⁡3⋅x+π9+1•Apply the horizontal shift and stretch to the range,x=−2⁢π..2⁢π−2⁢π⋅13+π9..2⁢π⋅13+π9=−2.443460953..1.745329252•We can now plot using the information extractedPLOT⁡...
CurveSketchSteps⁡2⁢x2+4⁢x+10
Let's plot2⁢x2+4⁢x+102⋅x2+4⋅x+10•Complete the square2⁢x+12+8•With the expression in vertex form we can extract valuable information2⋅x+12+8•The coefficient2of thex+12term indicates a parabola that opensupand has a verticalstretchof22⋅x+12+8•We have a horizontal shift of−1and a vertical shift of8which gives a vertex of (−1,8)2⋅x+12+8•We can now plot using the information extractedPLOT⁡...
CurveSketchSteps⁡4⁢x+10,output=typeset
Let's plot4⁢x+104⋅x+10•This is a line; find two points and draw a line through themy=4⁢x+10•Setx= 0 to solve for y intercepty=10•This gives a y intercept of (0,10)y=10•Set expresson to 0 to solve forxintercept0=4⋅x+10•Rearrange expression4⋅x+10=0•Subtract10from both sides4⋅x+10−10=0−10•Simplify4⋅x=−10•Divide both sides by44⋅x4=−104•Simplifyx=−52•This gives anxintercept of (−52,0)x=−52•By connecting through the two points we can plot the linePLOT⁡...
CurveSketchSteps⁡23⁢x+2,output=link
https://learn.maplesoft.com/d/GSFGIHMLARGPFKFTJPNMOFENFUEHOLNUBJBIFUIMORFQFHHRFIGUJPIFNHCRJLAOERDSHUNHJOJNAODNEMNUFKOHFKLJIPCOIJCU
The Student[Basics][CurveSketchSteps] command was introduced in Maple 2022.
For more information on Maple 2022 changes, see Updates in Maple 2022.
See Also
Student:-Basics
Student:-Basics:-FactorSteps
Student:-Basics:-LinearSolveSteps
Student:-Basics:-OutputStepsRecord
Student:-Calculus1:-ShowSolution
Student:-Calculus1:-ShowSteps
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