Appendix

A-5: Evaluation

Example A-5.2

$$ The volume of a right circular cone is $V\=\mathrm{\π} r^2 h\/3$. Evaluate $V$ for $r\=3$ and $h\=5$. (This "double substitution" is known as simultaneous substitution.)   Solution Interactive Solution   •  Control-drag (or type) the expression for V. •  Context Panel: Evaluate at a Point≻$r\=3\,h\=5$ $\mathrm{\pi } r^2 h\/3$$\stackrel{\text{evaluate at point}}{\to }$$15\mathrm{\π}$ Alternative solution •  Expression palette: Evaluation template $\genfrac{}{}{0ex}{}{\mathrm{\π} r^{2}h\/3}{\phantom{x\=a}}|\genfrac{}{}{0ex}{}{\phantom{\mathrm{f(x)}}}{r\=3\,h\=5}$ = $15\mathrm{\π}$$$ $$ Coded Solution $$ •  Use the eval command. The brackets around the substitution rules are essential. >  $\mathrm{eval}\left(\mathrm{\π} r^{2}h\/3\,\left[r\=3\,h\=5\right]\right)$ $$

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