Chapter 5: Double Integration
Section 5.3: Regions with Curved Boundaries
Example 5.3.9
Integrate fx,y=1+2 x2+3 y2 over the region bounded by the ellipse 4 x2+9 y2=36 and the line y=2−1+5/3x.
Solution
Mathematical Solution
To iterate in the order dx dy, describe the bounding curves as in Figure 5.3.9(a) where xL=345−3 y−2 is the lower limit of the inner integral, and xR=324−y2 is the upper limit. The limits on the outer integral are yB=−25/3 and yT=2. The expression for xL is obtained by solving the equation y=2−1+5/3x for x=xy. Consequently, the iteration in the order dx dy leads to
∫−2352∫345−3 y−2324−y21+2 x2+3 y2 ⅆx ⅆy
= 51⁢arcsin⁢361+ 5⁢+735−143
≐55.83
Figure 5.3.9(b) suggests that iteration in the order dy dx requires two different doubly iterated integrals. In the red region, yL=2−1+5/3x but in the green region, yL=−29−x2/3. In both regions, yT=−29−x2/3. This more tedious iteration is not pursued further.
Figure 5.3.9(a) Iterating in the order dx dy
Figure 5.3.9(b) Iterating in the order dy dx
Maple Solution - Interactive
Initialize
Tools≻Load Package: Student Multivariate Calculus
Loading Student:-MultivariateCalculus
Context Panel: Assign Name
f=1+2 x2+3 y2→assign
XL=345−3 y−2→assign
XR=34−y2/2→assign
YB=−25/3→assign
Access the MultiInt command via the Context Panel
Write f, the name of the integrand. Context Panel: Evaluate and Display Inline
Context Panel: Student Multivariate Calculus≻Integrate≻Iterated Fill in both panes (see Figures 5.3.(1, 2)) and select "integral" for the Output
Context Panel: Approximate≻10 (digits)
f = 2⁢x2+3⁢y2+1→MultiInt∫−23⁢52∫34⁢5−3⁢y−232⁢−y2+42⁢x2+3⁢y2+1ⅆxⅆy→at 10 digits55.83116045
Table 5.3.9(b) illustrates the visualization task template keyed to iterate in the order dx dy.
Tools≻Tasks≻Browse:
Calculus - Multivariate≻Integration≻Visualizing Regions of Integration≻
Evaluate ∬RΨx,y dA and Graph R
Area Element dA
Select dAdy dxdx dy
, Ψ=
Value of Integral
G=
b=
g=
a=
Bounding Curves
"Volume"
Table 5.3.9(b) Visualizing R and the resulting volume for iteration in the order dy dx
The horizontal arrow in the left-hand graph indicates that the iteration is in the order dx dy, whereby the first (or inner) integration is in the horizontal direction, from the leftmost boundary curve to the rightmost. Because the integrand is positive, the double integral calculates the volume below the surface z=f but above the plane z=0. The solid whose volume is thereby calculated is seen in the right-hand graph.
The detailed analytic results below are obtained via the palettes and Context Panel.
Iterate in the order dy dx
Calculus palette: Template for definite iterated double integral
Context Panel: Evaluate and Display Inline
∫YB2∫XLXRf ⅆx ⅆy = 51⁢arcsin⁡16⁢3+16⁢5⁢3−989+73⁢5→at 10 digits55.83116051
Display the iterated integrals
Calculus palette: Template for definite iterated double integral Context Panel: 2-D Math≻Convert To≻Inert Form Press the Enter key
Context Panel: Evaluate Integral
∫YB2∫XLXRf ⅆx ⅆy
∫−23⁢52∫34⁢5−3⁢y−232⁢−y2+42⁢x2+3⁢y2+1ⅆxⅆy
=
51⁢arcsin⁡16⁢3+16⁢5⁢3−989+73⁢5
Note: The calculations by which the expression for xL=345−3 y−2 is obtained are as follows.
Context Panel: Solve≻Obtain Solutions for≻x
Context Panel: Rationalize
y=2−1+5/3 x→solutions for x−3⁢y−23+5= rationalize 34⁢5−3⁢y−2
Maple Solution - Coded
Install the Student MultivariateCalculus package.
withStudent:-MultivariateCalculus:
Define the integrand.
f≔1+2 x2+3 y2:
Define xL=gy.
XL≔345−3 y−2:
Define xR=Gy.
XR≔34−y2/2:
Define yB.
YB≔−25/3:
Iterate in the order dx dy
Use the Int command to obtain the inert integral and the int command for immediate evaluation
Intf,x=XL..XR,y=YB..2;intf,x=XL..XR,y=YB..2
Use the MultiInt command from the Student MultivariateCalculus package
MultiIntf,x=XL..XR,y=YB..2,output=integral
MultiIntf,x=XL..XR,y=YB..2
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