Chapter 8: Infinite Sequences and Series
Section 8.2: Series
Example 8.2.6
Test the series ∑n=1∞arctann for convergence.
Solution
Determine the limiting behavior of an=arctann
Calculus palette: Limit template≻Apply to arctann
Context Panel: Evaluate and Display Inline
limn→∞arctann = 12⁢π
Because an=arctann→π/2 and not 0 as n→∞, the series cannot converge. Hence it must diverge.
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