Chapter 3: Functions of Several Variables
Section 3.2: Limits and Continuity
Example 3.2.4
For f=x y2x2+y4, show that the bivariate limit at the origin does not exist.
Solution
Mathematical Solution
Evaluate the limit along parabolas of the form y=m x, that is, evaluate
limx→0fx,m x
=limx→0m2 x2x2+m4x2
=limx→0m21+m4
=m21+m4
Since the limit depends on the direction of approach to the origin, the bivariate limit at the origin does not exist.
Maple Solution - Interactive
Define the function fx,y
Context Panel: Assign Function
fx,y=x y2x2+y4→assign as functionf
Evaluate limx→0fx,m x
Calculus palette: Limit operator
Context Panel: Evaluate and Display Inline
limx→0fx,m x = m2m4+1
Since the limit depends on the direction of approach to the origin, the bivariate limit at the origin does not exist. Alternatively, access Maple's bivariate limit through the Context Panel.
Context Panel: Limit (Bivariate) (Fill in the Limit Point dialog as per Figure 3.2.4(a).)
Figure 3.2.4(a) Limit Point dialog
fx,y = xy2y4+x2→bivariate limit−12..12
The return of a range indicates the limit does not exist.
Maple Solution - Coded
Define the function fx,y.
f≔x,y→x y2x2+y4:
Apply the limit command to fx,m x. Context Panel: Evaluate and Display Inline
limitfx,m x,x=0 = m2m4+1
For corroboration, apply Maple's bivariate limit command
Obtain the bivariate limit.
limitfx,y,x=0,y=0 = −12..12
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