Chapter 5: Double Integration
Section 5.7: Double Integration in Polar Coordinates
Example 5.7.1
Calculate the area of contained in one loop of the 4-leaf rose r=cos2 θ.
Solution
Mathematical Solution
Figure 5.7.1(a) shows the 4-leaf rose, and, in green, the region whose area is to be calculated.
Figure 5.7.1(b) is an animation in which the 4-leaf rose is drawn under the action of the slider in the animation toolbar. The polar angle appears above the vertical axis. Use this animation to infer the appropriate angles for the iterated double integral that follows.
Inspired by the animation in Figure 5.7.1(b), Figure 5.7.1(c) is a graph of cos2 θ. It suggests that the zeros of this function are odd multiples of π/4. The shaded loop in Figure 5.7.1(a) is traced for θ∈−π/4,π/4.
use plots in module() local p1,p2,p3; p1:=plot([cos(2*t),t,t=0..2*Pi],coords=polar,color=black); p2:=plot([cos(2*t),t,t=-(1/4)*Pi..(1/4)*Pi],coords=polar,filled=[color=green], color=black); p3:=display(p1,p2,tickmarks=[3,3],labels=[x,y],view=[-1..1,-1..1]); print(p3); end module: end use:
Figure 5.7.1(a) Region
plots:-animate(plot,[cos(2*t),t=0..theta,coords=polar,view=[-1..1,-1..1]],theta=0..2*Pi,frames=37,scaling=constrained,labels=[x,y],tickmarks=[3,3]);
Figure 5.7.1(b) Animation
Figure 5.7.1(c) Zeros
The area of the region shaded in green in Figure 5.7.1(a) is
∫−π/4π/4∫0cos2 θr ⅆr ⅆθ = π/8
Maple Solution - Interactive
Initialize
Tools≻Load Package: Student Multivariate Calculus
Loading Student:-MultivariateCalculus
Access the MultiInt command via the Context Panel
Type the integrand, 1.
Context Panel: Student Multivariate Calculus≻Integrate≻Iterated Fill in the fields of the two dialogs shown below
Context Panel: Evaluate Integral
1→MultiInt∫−14π14π∫0cos2θrⅆrⅆθ=18π
The task template in Table 5.7.1(a) can be used to visualize the region of integration over which a given iterated integral acts. Select an order of integration, and provide an integrand of 1 to compute area. Supply the limits of integration, and use the Exact button to obtain the value of the iterated integral, and the Draw Graphs button to obtain the two figures provided by the task template.
Tools≻Tasks≻Browse:
Calculus - Multivariate≻Integration≻Visualizing Regions of Integration≻Polar
Evaluate ∬RΨr,θ dA and Graph R
Area Element dA
r dr dθ
r dθ dr
, Ψ=
Value of Integral
G=
b=
g=
a=
Bounding Curves
"Volume"
Table 5.7.1(a) Task template for visualizing a polar region of integration
The figure on the left is an animation that shows how the radial cone representing dθ traverses the region of integration. The figure on the right is a representation of the volume of a solid of height 1, with base the region of integration. Since the height is 1, the number computed for the volume is the same number as the area. If this figure is rotated and viewed from above, it appears to be a shaded version of the region of integration. These visual clues help to decide of the polar area has been properly identified and calculated.
The details of an interactive calculation of the required area appear in Table 5.7.1(b).
Tools≻Load Package: Student Calculus 1
Loading Student:-Calculus1
Find the zeros of cos2 θ
Write the equation.
Context Panel: Student Calculus1≻Solve≻Find Roots Complete the dialog as per Figure 5.7.1(d)
Figure 5.7.1(d) Roots dialog
cos2 θ=0→roots−34π,−14π,14π,34π,54π,74π
Implement and evaluate the iterated integral
Calculus palette: Iterated double integral template
Context Panel: Evaluate and Display Inline
∫−π/4π/4∫0cos2 θr ⅆr ⅆθ = 18π
Table 5.7.1(b) Details of the interactive calculation of the required area.
<< Chapter Overview Section 5.7 Next Example >>
© Maplesoft, a division of Waterloo Maple Inc., 2024. All rights reserved. This product is protected by copyright and distributed under licenses restricting its use, copying, distribution, and decompilation.
For more information on Maplesoft products and services, visit www.maplesoft.com
Download Help Document
