Chapter 6: Applications of Double Integration
Section 6.4: Average Value
Example 6.4.8
Find the average value of Fr,θ=r2 over R, the region that is inside the circle r=3 sinθ but outside the cardioid r=1+sinθ. See Example 5.7.3.
Solution
Mathematical Solution
Figure 6.4.8(a) shows the function Fr,θ drawn over the region R. The integral in the numerator for the average value is over the shaded region. The average value itself is then
∫π/65 π/6∫1+sinθ3 sin θF⋅r ⅆr ⅆθ∫π/65 π/6∫1+sinθ3 sin θr ⅆr ⅆθ
=94⁢3+133⁢ππ
=94⁢3π+133
≐5.573823348
Figure 6.4.8(a) Graph of Fr,θ
Maple Solution - Interactive
The simplest approach to finding the average value in polar coordinates is to use the task template shown in Table 6.4.8(a).
Tools≻Tasks≻Browse:
Calculus - Multivariate≻Integration≻Average Value≻Polar
Average Value of a Function in Polar Coordinates
Integrand
r2
Region: r1θ≤r≤r2θ,a≤θ≤b
r1θ
1+sinθ
1+sin⁡θ
r2θ
3 sinθ
3⁢sin⁡θ
a
π/6
16⁢π
b
5 π/6
56⁢π
Inert Integral: dr dθ
(Note automatic insertion of Jacobian.)
StudentMultivariateCalculusFunctionAverage,r=..,θ=..,coordinates=polarr,θ,output=integral
∫16⁢π56⁢π∫1+sin⁡θ3⁢sin⁡θr3ⅆrⅆθ∫16⁢π56⁢π∫1+sin⁡θ3⁢sin⁡θrⅆrⅆθ
Value
StudentMultivariateCalculusFunctionAverage,r=..,θ=..,coordinates=polarr,θ
94⁢3+133⁢ππ
Table 6.4.8(a) In polar coordinates, computation of average value by task template
A solution from first principles is implemented in Table 6.4.8(b).
Initialize
Context Panel: Assign name
F=r2→assign
Calculate the average value of F
Calculus palette: Iterated double-integral template
Context Panel: Evaluate and Display Inline
Context Panel: Expand≻Expand
Context Panel: Approximate≻10 (digits)
∫5 π/6π/6∫1+sinθ3 sin θF⋅r ⅆr ⅆθ∫5 π/6π/6∫1+sinθ3 sin θr ⅆr ⅆθ = −−94⁢3−133⁢ππ= expand 94⁢3π+133→at 10 digits5.573823348
Table 6.4.8(b) From first principles and in polar coordinates, calculation of average value
Maple Solution - Coded
Define F.
F≔r2:
Compute the average value of F
Apply the FunctionAverage command from the Student MultivariateCalculus package.
Use the expand and evalf commands to modify the form of the average value.
Student:-MultivariateCalculus:-FunctionAverageF,r=1+sinθ..3 sinθ,θ=π/6..5 π/6,coordinates=polarr,θ,output=integral
q≔Student:-MultivariateCalculus:-FunctionAverageF,r=1+sinθ..3 sinθ,θ=π/6..5 π/6,coordinates=polarr,θ
expandq = 94⁢3π+133
evalfq = 5.573823350
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