Chapter 7: Triple Integration
Section 7.4: Integration in Cylindrical Coordinates
Example 7.4.6
Use cylindrical coordinates to integrate the function f=1 over R, the region outside the cylinder x2+y2=1, bounded above by z=9−x2−y2, and below by z=0.
Solution
Mathematical Solution
Figure 7.4.6(a) shows the region R. In cylindrical coordinates, the upper surface of R is
Zr,θ=9−r2
while the lower surface is zr,θ= 0.
The two surfaces meet in a circle of radius 3 in the plane z=0.
The iteration in the order dz dr dθ is found to be
∫02 π∫13∫ 09−r2r dz dr dθ=32 π
Figure 7.4.6(a) The region R
Maple Solution - Interactive
In cylindrical coordinates, the upper surface of R is Zr,θ=9−r2, while the lower surface is zr,θ= 0. The two surfaces meet in a circle of radius 3 in the plane z=0. The region outside the cylinder but inside the upper surface extends from r=1 to r=3.
Table 7.4.6(a) provides a solution by a visualization task template. After selecting the order of iteration, the integrand and the fields for the limits of integration are given. The resulting value of the integral and a graph of the region of integration are generated by pressing the appropriate buttons.
Tools≻Tasks≻Browse:
Calculus - Multivariate≻Integration≻Visualizing Regions of Integration≻Cylindrical
Evaluate ∭RΨr,θ,z dv and Graph R
Volume Element dv
r dz dr dθ
r dz dθ dr
r dr dθ dz
r dr dz dθ
r dθ dr dz
r dθ dz dr
, where Ψ=
F=
G=
b=
f=
g=
a=
Table 7.4.6(a) Task template for iterating a triple integral in cylindrical coordinates
Constrained scaling is applied to the graph via its Context Panel.
Table 7.4.6(b) provides a solution from first principles. Note that the Jacobian, r, must be inserted into the integrand.
Calculus palette: Iterated triple-integral template
Context Panel: Evaluate and Display Inline
∫02 π∫13∫ 09−r2r ⅆz ⅆr ⅆθ = 32⁢π
Table 7.4.6(b) Solution from first principles
Table 7.4.6(c) provides a solution by a task template that uses the MultiInt command from the Student MultivariateCalculus package, and iterates in the order dz dr dθ. The command takes a coordinate option, and hence, inserts the appropriate Jacobian automatically.
Tools≻Tasks≻Browse: Calculus - Multivariate≻Integration≻Multiple Integration≻Cylindrical
Iterated Triple Integral in Cylindrical Coordinates
Integrand:
1
Region: z1r,θ≤z≤z2r,θ,r1θ≤r≤r2θ,a≤θ≤b
z1r,θ
0
z2r,θ
9−r2
−r2+9
r1θ
r2θ
3
a
b
2 π
2⁢π
Inert Integral: dz dr dθ
(Note automatic insertion of Jacobian.)
StudentMultivariateCalculusMultiInt,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z,output=integral
∫02⁢π∫13∫0−r2+9rⅆzⅆrⅆθ
Value:
StudentMultivariateCalculusMultiInt,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z
32⁢π
Stepwise Evaluation:
StudentMultivariateCalculusMultiInt,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z,output=steps
∫02⁢π∫13∫0−r2+9rⅆzⅆrⅆθ=∫02⁢π∫13r⁢zz=0..−r2+9|r⁢zz=0..−r2+9ⅆrⅆθ=∫02⁢π∫13r⁢−r2+9ⅆrⅆθ=∫02⁢π−14⁢r4+92⁢r2r=1..3|−14⁢r4+92⁢r2r=1..3ⅆθ=∫02⁢π16ⅆθ=16⁢θθ=0..2⁢π|16⁢θθ=0..2⁢π
Table 7.4.6(c) Solution by task template that implements the MultiInt command
Initialize
Tools≻Load Package: Student Multivariate Calculus
Loading Student:-MultivariateCalculus
Access the MultiInt command via the Context Panel
Type the integrand, 1.
Context Panel: Student Multivariate Calculus≻Integrate≻Iterated Fill in the fields of the two dialogs shown below.
Context Panel: Evaluate Integral
1→MultiInt∫02⁢π∫13∫0−r2+9rⅆzⅆrⅆθ=32⁢π
Maple Solution - Coded
Install the Student MultivariateCalculus package.
withStudent:-MultivariateCalculus:
Top-level solution using the Int and int commands
Intr,z= 0..9−r2,r=1..3,θ=0..2 π=intr,z= 0..9−r2,r=1..3,θ=0..2 π
∫02⁢π∫13∫0−r2+9rⅆzⅆrⅆθ=32⁢π
Solution via the MultiInt command from the Student MultivariateCalculus package
MultiInt1,z= 0..9−r2,r=1..3,θ=0..2 π,coordinates=cylindrical,output=integral=MultiInt1,z= 0..9−r2,r=1..3,θ=0..2 π,coordinates=cylindrical
MultiInt1,z= 0..9−r2,r=1..3,θ=0..2 π,coordinates=cylindrical,output=steps
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