Chapter 8: Applications of Triple Integration
Section 8.2: Average Value
Example 8.2.7
Obtain the average value of fr,θ,z=r2+z sinθ/4 over R, the region that is inside the cylinder x2+y2=9 and between the planes z=0 and y+z=5. (See Example 8.1.15.)
Solution
Mathematical Solution
The average value of f over R is defined as ∫∫∫Rf dv∫∫∫R1 dv. For the given values of f and R, obtain
∫02⁢π∫03∫05−r⁢sin⁡θr2+z⁢sinθ/4 r dz dr dθ∫02⁢π∫03∫05−r⁢sin⁡θr dz dr dθ = 13132217545 π = 437742625⁢π
Maple Solution - Interactive
Because the triple integral over R can be iterated in cylindrical coordinates in the order dz dr dθ, the task template in Table 8.2.7(a), implementing the FunctionAverage command from the Student MultivariateCalculus package, can be used.
Tools≻Tasks≻Browse: Calculus - Multivariate≻Integration≻Average Value≻Cylindrical
Average Value of a Function in Cylindrical Coordinates
Integrand
r2+zsinθ/4
r2+z⁢sin⁡θ4
Region: z1r,θ≤z≤z2r,θ,r1θ≤r≤r2θ,a≤θ≤b
z1r,θ
0
z2r,θ
5−r sinθ
5−r⁢sin⁡θ
r1θ
r2θ
3
a
b
2 π
2⁢π
Inert Integral: dz dr dθ
(Note automatic insertion of Jacobian.)
StudentMultivariateCalculusFunctionAverage,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z,output=integral
∫02⁢π∫03∫05−r⁢sin⁡θr2+z⁢sin⁡θ4⁢rⅆzⅆrⅆθ∫02⁢π∫03∫05−r⁢sin⁡θrⅆzⅆrⅆθ
Value
StudentMultivariateCalculusFunctionAverage,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z
437742625⁢π
Table 8.2.7(a) Solution by task template implementing the FunctionAverage command
To implement a solution from first principles, evaluate the integral of f over R and divide by the volume computed in Example 8.1.15. To integrate f over R, use the visualization task template in Table 8.2.7(b).
Tools≻Tasks≻Browse: Calculus - Multivariate≻Integration≻Visualizing Regions of Integration≻Cylindrical
Evaluate ∭RΨr,θ,z dv and Graph R
Volume Element dv
r dz dr dθ
r dz dθ dr
r dr dθ dz
r dr dz dθ
r dθ dr dz
r dθ dz dr
, where Ψ=
F=
G=
b=
f=
g=
a=
Table 8.2.7(b) Integration of f over R by visualization task template
Table 8.2.7(c) completes the solution from first principles.
Copy and paste the value of ∫∫∫Rf dv
Divide by the volume of R from Example 8.1.15
Context Panel: Evaluate and Display Inline
131322175/45 π = 437742625⁢π
Table 8.2.7(c) Completion of the solution from first principles
Maple Solution - Coded
Initialize
Install the Student MultivariateCalculus package.
withStudent:-MultivariateCalculus:
Define the function f.
f≔r2+z sinθ/4:
Apply the FunctionAverage command from the Student MultivariateCalculus package
FunctionAveragef,z=0..5−r sinθ,r=0..3,θ=0..2 π,coordinates=cylindricalr,θ,z
From first principles, verify this result by integrating f over R and dividing by V, the volume of R.
Use the MultiInt command to obtain Q, the integral of f over R
Q≔MultiIntf,z=0..5−r sinθ,r=0..3,θ=0..2 π,coordinates=cylindricalr,θ,z
Q≔131322175
Use the MultiInt command to obtain V, the volume of R
V≔MultiInt1,z=0..5−r sinθ,r=0..3,θ=0..2 π,coordinates=cylindricalr,θ,z
V≔45⁢π
Divide Q by V
Q/V = 437742625⁢π
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