Chapter 8: Applications of Triple Integration
Section 8.3: First Moments
Example 8.3.2
Obtain the centroid of R, the wedge the planes z=y and z=0 cut from the cylinder x2+y2=4.
Impose the density δr,θ,z=r z2cosθ/3 on R and find the resulting center of mass.
(See Example 8.1.5.)
Solution
Mathematical Solution
The volume of R, found in Example 8.1.5, is given by
V=∫0π∫02∫0r sinθr dz dr dθ = 163
Table 8.3.2(a) lists the first moments and the coordinates of the centroid.
First Moments
Centroid
Myz=∫0π∫02∫0r⁢sin⁡θcosθ⁢r2 dz dr dθ = 0
x&conjugate0;=MyzV=0V=0
Mxz=∫0π∫02∫0r⁢sin⁡θr2⁢sinθ dz dr dθ = 2 π
y&conjugate0;=MxzV=2 π163=3 π8
Mxy=∫0π∫02∫0r⁢sin⁡θz⁢r dz dr dθ = π
z&conjugate0;=MxyV=π163 = 3 π16
Table 8.3.2(a) First moments and the coordinates of the centroid
When the region R supports the density δr,θ,z=r z2cosθ/3, the total mass in R is
m=∫0π∫02∫0r⁢sin⁡θr2⁢z2⁢cosθ3 dz dr dθ = 8120
Table 8.3.2(b) lists the first moments and the coordinates of the center of mass under this condition.
Center of Mass
Myz = ∫0π∫02∫0r⁢sin⁡θcosθ⁢r3⁢z2⁢cosθ3 dz dr dθ = 1036835035
x&conjugate0;=Myzm=10368350358120 = 5127007
Mxz = ∫0π∫02∫0r⁢sin⁡θr3⁢sinθ⁢z2⁢cosθ3 dz dr dθ = 12441635035⁢3
y&conjugate0;=Mxzm=12441635035⁢38120 = 61447007⁢3
Mxy = ∫0π∫02∫0r⁢sin⁡θz3⁢r2⁢cosθ3 dz dr dθ = 9331235035⁢3
z&conjugate0;=Mxym=9331235035⁢38120 = 46087007⁢3
Table 8.3.2(b) First moments and the coordinates of the center of mass
In each integral, the Jacobian r must be inserted, and where applicable, the "lever arms" x and y are replaced respectively by x=r cosθ, y=r sinθ.
Maple Solution - Interactive
Based on the CenterOfMass command in the Student MultivariateCalculus package, the task template in Table 8.3.2(c) will find the centroid of R when the density is set to 1.
Tools≻Tasks≻Browse: Calculus - Multivariate≻Integration≻Center of Mass≻Cylindrical
Center of Mass for 3-D Region in Cylindrical Coordinates
Density:
1
Region: z1r,θ≤z≤z2r,θ,r1θ≤r≤r2θ,a≤θ≤b
z1r,θ
0
z2r,θ
r sinθ
r⁢sin⁡θ
r1θ
r2θ
2
a
b
π
Moments ÷ Mass:
Inert Integral - dz dr dθ
StudentMultivariateCalculusCenterOfMass,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z,output=integral
∫0π∫02∫0r⁢sin⁡θcos⁡θ⁢r2ⅆzⅆrⅆθ∫0π∫02∫0r⁢sin⁡θrⅆzⅆrⅆθ,∫0π∫02∫0r⁢sin⁡θr2⁢sin⁡θⅆzⅆrⅆθ∫0π∫02∫0r⁢sin⁡θrⅆzⅆrⅆθ,∫0π∫02∫0r⁢sin⁡θz⁢rⅆzⅆrⅆθ∫0π∫02∫0r⁢sin⁡θrⅆzⅆrⅆθ
Explicit values for r&conjugate0;, θ&conjugate0;, and z&conjugate0;, the center of mass given in cylindrical coordinates:
StudentMultivariateCalculusCenterOfMass,z=..,r=..,θ=..,coordinates=cylindricalr,θ,z
38⁢π,12⁢π,316⁢π
Table 8.3.2(c) Centroid computed by task template that implements the CenterOfMass command
Based on the CenterOfMass command in the Student MultivariateCalculus package, the task template in Table 8.3.2(d) will find the center of mass of R for a given density.
r z2cosθ/3
r⁢z2⁢cos⁡13⁢θ
∫0π∫02∫0r⁢sin⁡θcos⁡θ⁢r3⁢z2⁢cos⁡13⁢θⅆzⅆrⅆθ∫0π∫02∫0r⁢sin⁡θr2⁢z2⁢cos⁡13⁢θⅆzⅆrⅆθ,∫0π∫02∫0r⁢sin⁡θr3⁢sin⁡θ⁢z2⁢cos⁡13⁢θⅆzⅆrⅆθ∫0π∫02∫0r⁢sin⁡θr2⁢z2⁢cos⁡13⁢θⅆzⅆrⅆθ,∫0π∫02∫0r⁢sin⁡θz3⁢r2⁢cos⁡13⁢θⅆzⅆrⅆθ∫0π∫02∫0r⁢sin⁡θr2⁢z2⁢cos⁡13⁢θⅆzⅆrⅆθ
5127007⁢433,arctan⁡12⁢3,46087007⁢3
Table 8.3.2(d) Centroid computed by task template that implements the CenterOfMass command
Maple Solution - Coded
In Table 8.3.2(e), the centroid of R is obtained via the CenterOfMass command from the Student MultivariateCalculus package, provided the density is set equal to 1.
Initialize
Install the Student MultivariateCalculus package.
withStudent:-MultivariateCalculus:
Apply the CenterOfMass command from the Student MultivariateCalculus package
CenterOfMass1,z=0..r sinθ,r=0..2,θ=0..π,coordinates=cylindricalr,θ,z,output=integral
C≔CenterOfMass1,z=0..r sinθ,r=0..2,θ=0..π,coordinates=cylindricalr,θ,z
Table 8.3.2(e) Centroid in cylindrical coordinates
The coordinates C = 38⁢π,12⁢π,316⁢π are cylindrical; the Cartesian equivalents, obtained by making the appropriate substitutions, are then
evalr cosθ,r sinθ,z,Equater,θ,z,C = 0,38⁢π,316⁢π
In Table 8.3.2(f), the center of mass is obtained via the CenterOfMass command from the Student MultivariateCalculus package.
Define the density δ.
δ≔r z2cosθ/3:
CenterOfMassδ,z=0..r sinθ,r=0..2,θ=0..π,coordinates=cylindricalr,θ,z,output=integral
CM≔simplifyCenterOfMassδ,z=0..r sinθ,r=0..2,θ=0..π,coordinates=cylindricalr,θ,z
Table 8.3.2(f) Center of mass in cylindrical coordinates
The coordinates
CM = 5127007⁢433,arctan⁡12⁢3,46087007⁢3
are cylindrical; the Cartesian equivalents, obtained by making the appropriate substitutions, are then
cm≔evalr cosθ,r sinθ,z,Equater,θ,z,CM
5127007,61447007⁢3,46087007⁢3
evalfcm = 0.07306978736,1.518727011,1.139045258
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