Chapter 9: Vector Calculus
Section 9.10: Green's Theorem
Example 9.10.6
Apply the divergence-form of Green's theorem to F=x−2 y i+x2y j, and R, the region bounded by the parabola y=x2 and the line y=x+1.
Solution
Mathematical Solution
Figure 9.10.6(a) shows the region R, bounded by the curves y=x2 and y=x+1, curves that intersect at x±=1 ±5/2.
Since ∇·F=1+x2, the left side of the divergence-form of Green's theorem becomes
∫1−521+52∫x2x+11+x2 dy dx=5 5/4
The flux through the boundary of R is the sum of two separate flux integrals, namely,
Figure 9.10.6(a) The region R
∫1− 521+52x−2 x2⋅2 x−x4 dx+∫1+521− 52x−2x+1−x2x+1 dx
where the first integral is from left to right along y=x2; and the second, from right to left, is along y=x+1. The left-hand integral of f dy−g dx evaluates to −85/3; the right-hand integral, to 475/12. The sum is 55/4.
Maple Solution - Interactive
The divergence of F is integrated over the region R in Table 9.10.6(a).
Initialize
Tools≻Load Package: Student Vector Calculus
Loading Student:-VectorCalculus
Tools≻Tasks≻Browse: Calculus - Vector≻ Vector Algebra and Settings≻ Display Format for Vectors
Press the Access Settings button and select "Display as Column Vector"
Display Format for Vectors
Define the Cartesian vector field F
Write the vector field as a free vector. Context Panel: Evaluate and Display Inline
Context Panel: Student Vector Calculus≻Conversions≻To Vector Field
Context Panel: Assign to a Name≻F
x−2 y,x2y = →to Vector Field →assign to a nameF
Compute the divergence of F
Common Symbols palette: Del and dot product operators
Context Panel: Evaluate and Display Inline
∇·F = x2+1
Obtain the x-coordinates of the intersections of y=x2 and y=x+1
Write the relevant equation.
Context Panel: Solve≻Obtain Solutions for≻x
Context Panel: Assign to a Name≻X
x2=1+x→solutions for x12⁢5+12,12−12⁢5→assign to a nameX
Form, evaluate, and simplify the integral of the divergence
Tools≻Load Package: Student Multivariate Calculus
Loading Student:-MultivariateCalculus
Type 1+x2 and press the Enter key.
Context Panel: Student Multivariate Calculus≻Integrate≻Iterated Complete the two dialogs as per the figures below.
Context Panel: Evaluate Integral
Context Panel: Simplify≻Simplify
1+x2
x2+1
→MultiInt
∫12−12⁢512⁢5+12∫x21+xx2+1ⅆyⅆx
=
−15⁢12⁢5+125+15⁢12−12⁢55+14⁢12⁢5+124−14⁢12−12⁢54+12⁢12⁢5+122−12⁢12−12⁢52+5
= simplify
54⁢5
Table 9.10.6(a) ∇·F integrated over the region R
The flux of F through the boundary of R is obtained in Table 9.10.6(b), where f=F1 and g=F2. On the curve y=x2, dy=2 x dx, but on the curve y=1+x, dy=dx.
Compute ∳Cf dy−g dx, the flux of F through C, the boundary of R
Calculus palette: Definite integral template
Expression palette: Evaluation template
∫X2X1F1⋅2 x−F2x=a|f(x)y=x2 ⅆx= simplify −83⁢5
∫X1X2F1−F2x=a|f(x)y=1+xⅆx= simplify 4712⁢5
Table 9.10.6(b) Flux of F through the boundary of R
The net flux is the sum 4712−835=545.
Maple Solution - Coded
Install the Student VectorCalculus package.
withStudent:-VectorCalculus:
Use the BasisFormat command to set the display format for vectors.
BasisFormatfalse:
Define F with the VectorField command.
F≔VectorFieldx−2 y,x2y:
Obtain the x-coordinates of the intersections of y=x2 and y=x+1 by invoking the solve command.
X≔solvex2=x+1,x
12+12⁢5,12−12⁢5
Use the int command to integrate ∇·F over the region R
intDivergenceF,x,y=Region X2..X1,x2..x+1,output=integral
∫12−12⁢512+12⁢5∫x2x+1x2+1ⅆyⅆx
simplifyintDivergenceF,x,y=Region X2..X1,x2..x+1 = 54⁢5
Use the Flux command to obtain the flux of F through y=x2
FluxF,Pathx,x2,x=X2..X1,output=integral
∫12−12⁢512+12⁢52⁢−2⁢x2+x⁢x−x4ⅆx
Q1≔simplifyFluxF,Pathx,x2,x=X2..X1 = −83⁢5
Use the Flux command to obtain the flux of F through y=x+1
FluxF,Pathx,x+1,x=X1..X2,output=integral
∫12+12⁢512−12⁢5−x−2−x2⁢x+1ⅆx
Q2≔simplifyFluxF,Pathx,x+1,x=X1..X2 = 4712⁢5
Obtain the total flux through the boundaries of the region R
Q1+Q2 = 54⁢5
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