Appendix

A-6: Coordinate Geometry

Example A-6.2

$$ Obtain the equation of the perpendicular bisector of the line segment connecting the points $\left(7\,-3\right)$ and $\left(4\,-5\right)$.   Solution Interactive Solution   The task template whose path is   Tools≻Tasks≻Browse: Algebra≻Equation of a Line≻Perpendicular Bisector   gives $$ Perpendicular Bisector of the Line Segment between $\left(x_1\,y_1\right)$ and $\left(x_2\,y_2\right)$ $x_1\=$  $y_1\=$  $x_2\=$  $y_2\=$        $$ Coded Solution $$ Use the Slope, Midpoint, and Line commands from the Student Precalculus package.   •  Slope >  $m≔\mathrm{Student}\left[\mathrm{Precalculus}\right]\left[\mathrm{Slope}\right]\left(\left[7\,-3\right]\,\left[4\,-5\right]\right)$ •  Midpoint >  $\mathrm{MP}≔\mathrm{Student}\left[\mathrm{Precalculus}\right]\left[\mathrm{Midpoint}\right]\left(\left[7\,-3\right]\,\left[4\,-5\right]\right)$ •  Line, with slope as the negative reciprocal >  $\mathrm{Student}\left[\mathrm{Precalculus}\right]\left[\mathrm{Line}\right]\left(-\frac{1}{m}\,\mathrm{MP}\right)\left[1\right]$ $$

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