Chapter 6: Techniques of Integration
Section 6.7: Numeric Methods
Example 6.7.2
If λ is the "actual value" of the definite integral in Example 6.7.1, determine empirically (trial-and-error) the smallest partition for which λ and the Trapezoid rule's value agree when rounded to four places.
Solution
Mathematical Solution
From Example 6.7.1, λ=5.078061188, and rounded to four decimal places, λ becomes λ^=5.0781. By trial-and-error, the smallest value of n in the Trapezoid rule for which the approximation to the integral rounds to λ^ is n=312. The Trapezoid rule with this partition returns 5.078050007, which rounds up to λ^=5.0781.
Maple Solution
The tutor could be used to implement the Trapezoid rule for different values of the partition n. Alternatively, the ApproximateInt command can be use, as in Table 6.7.2(a).
Initialize
Tools≻Load Package: Student Calculus 1
Loading Student:-Calculus1
Context Panel: Assign to a Name≻F
1+sinxlnx+1→assign to a nameF
Apply the ApproximateInt command
ApproximateIntF,x=1..4.0,partition=311,method=trapezoid,output=value = 5.078049935
ApproximateIntF,x=1..4.0,partition=312,method=trapezoid,output=value = 5.078050007
Table 6.7.2(a) Determining n for which the Trapezoid rule agrees with λ when rounded to four places
At n=311, the Trapezoid rule yields 5.078049935, which rounds to 5.0780. On the other hand, at n=312, the Trapezoid rule yields 5.078050007, which rounds to 5.0781=λ^.
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