Chapter 8: Infinite Sequences and Series
Section 8.2: Series
Example 8.2.7
Test the series ∑n=1∞lnn5⁢n+2 for convergence.
Solution
Determine the limiting behavior of an=lnn5 n+2
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limn→∞lnn5 n+2 = −ln⁡5
Because an=lnn5 n+2→−ln5 and not 0 as n→∞, the series cannot converge. Hence it must diverge.
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