The Deal command differs from the Slice command in how the elements are ordered. Specifically, Slice keeps the elements in the same order. For example:

$L≔\left[\mathrm{seq}\left(1..5\right)\right]$

$L≔\left[1\,2\,3\,4\,5\right]$

$A≔\mathrm{Deal}\left(L\,3\right)$

$A≔\left[1\,4\right],\left[2\,5\right],\left[3\right]$

$B≔\mathrm{Slice}\left(L\,3\right)$

$B≔\left[1\,2\right],\left[3\,4\right],\left[5\right]$

Here, we will randomly construct a deck of cards (with typesetting!), and then deal five cards each to four players.

First, define  a list for the card ranks:

$\mathrm{Ranks}≔\left[\mathrm{seq}\left(2..10\right)\,''J''\,''Q''\,''K''\,''A''\right]$

$\mathrm{Ranks}≔\left[2\,3\,4\,5\,6\,7\,8\,9\,10\,''J''\,''Q''\,''K''\,''A''\right]$

Second, assemble typeset versions of all the cards available for each suit:

$\mathrm{Clubs}≔\mathrm{map}\left(z\mapsto \mathrm{Typesetting}:-\mathrm{mo}\left(\mathrm{cat}\left(z\,''♣''\right)\,\mathrm{mathcolor}=''Green''\right)\,\mathrm{Ranks}\right)$

$\mathrm{Clubs}≔\left[2♣\,3♣\,4♣\,5♣\,6♣\,7♣\,8♣\,9♣\,10♣\,J♣\,Q♣\,K♣\,A♣\right]$

$\mathrm{Diamonds}≔\mathrm{map}\left(z\mapsto \mathrm{Typesetting}:-\mathrm{mo}\left(\mathrm{cat}\left(z\,''♦''\right)\,\mathrm{mathcolor}=''Blue''\right)\,\mathrm{Ranks}\right)$

$\mathrm{Diamonds}≔\left[2♦\,3♦\,4♦\,5♦\,6♦\,7♦\,8♦\,9♦\,10♦\,J♦\,Q♦\,K♦\,A♦\right]$

$\mathrm{Hearts}≔\mathrm{map}\left(z\mapsto \mathrm{Typesetting}:-\mathrm{mo}\left(\mathrm{cat}\left(z\,''♥''\right)\,\mathrm{mathcolor}=''Red''\right)\,\mathrm{Ranks}\right)$

$\mathrm{Hearts}≔\left[2♥\,3♥\,4♥\,5♥\,6♥\,7♥\,8♥\,9♥\,10♥\,J♥\,Q♥\,K♥\,A♥\right]$

$\mathrm{Spades}≔\mathrm{map}\left(z\mapsto \mathrm{Typesetting}:-\mathrm{mo}\left(\mathrm{cat}\left(z\,''♠''\right)\,\mathrm{mathcolor}=''Black''\right)\,\mathrm{Ranks}\right)$

$\mathrm{Spades}≔\left[2♠\,3♠\,4♠\,5♠\,6♠\,7♠\,8♠\,9♠\,10♠\,J♠\,Q♠\,K♠\,A♠\right]$

Third, create a shuffled deck of the above cards:

$\mathrm{Deck}≔\mathrm{Statistics}:-\mathrm{Shuffle}\left(\left[\mathrm{seq}\left(\mathrm{Clubs}\right)\,\mathrm{seq}\left(\mathrm{Diamonds}\right)\,\mathrm{seq}\left(\mathrm{Hearts}\right)\,\mathrm{seq}\left(\mathrm{Spades}\right)\right]\right)$

$\mathrm{Deck}≔\left[8♦\,2♦\,5♥\,9♠\,7♥\,10♣\,Q♦\,3♣\,7♣\,Q♠\,6♠\,10♠\,K♠\,6♣\,Q♥\,A♥\,4♦\,J♥\,2♥\,Q♣\,9♣\,10♦\,7♦\,A♦\,8♠\,5♦\,K♣\,2♠\,3♥\,K♦\,6♦\,J♣\,9♦\,4♥\,A♠\,4♠\,5♣\,K♥\,J♦\,3♦\,9♥\,A♣\,4♣\,J♠\,6♥\,3♠\,8♣\,8♥\,10♥\,7♠\,2♣\,5♠\right]$

Finally, deal 5 cards each to the four players:

$\mathrm{Deal}\left(\mathrm{Deck}\left[..20\right]\,4\right)$

$\left[8♦\,7♥\,7♣\,K♠\,4♦\right],\left[2♦\,10♣\,Q♠\,6♣\,J♥\right],\left[5♥\,Q♦\,6♠\,Q♥\,2♥\right],\left[9♠\,3♣\,10♠\,A♥\,Q♣\right]$

Consider the following string:

$\mathrm{str}≔''I\; was\; born\; in\; the\; year\; 1950,\; graduated\; university\; in\; 1973,\; and\; retired\; in\; 2010.''$

$\mathrm{str}≔''I\; was\; born\; in\; the\; year\; 1950,\; graduated\; university\; in\; 1973,\; and\; retired\; in\; 2010.''$

Suppose we want to extract the years from this string. One way to accomplish this is to use regular expressions and split the string at the sub-strings that consist of four consecutive digits:

$\mathrm{Splits}≔\left[\mathrm{StringTools}:-\mathrm{RegSplit}\left(''[0-9]\{4\}''\,\mathrm{str}\,\mathrm{keepsplits}\right)\right]$

$\mathrm{Splits}≔\left[''I\; was\; born\; in\; the\; year''\,''1950''\,'',\; graduated\; university\; in''\,''1973''\,'',\; and\; retired\; in''\,''2010''\,''.''\right]$

This list stores the strings between the matches (years) and, since keepsplits=true, the years as well. Since the years are stored in the elements with even indices:

$\mathrm{Years}≔\mathrm{Deal}\left(\mathrm{Splits}\,2\,2\right)$

$\mathrm{Years}≔\left[''1950''\,''1973''\,''2010''\right]$