The function compose(f,g) interprets the expressions f and g as functions of s and t, respectively, and returns an expression that represents the function f(g(t)). Here, s and t are the default symbols of f (given by findsym(f,1)) and g (given by findsym(g,1)), respectively.

The function compose(f,g,z) treats f and g as functions of s and t, as described above, and returns an expression that represents the function f(g(z)).

The function compose(f,g,x,z) treats f as a function of x, g as a function of the default symbol, and returns an expression that represents the function f(g(z)).

The function compose(f,g,x,y,z) treats f as a function of x, g as a function of y, and returns an expression that represents the function f(g(z)).

$\mathrm{with}\left(\mathrm{MTM}\right)\:$

$f≔n-n^2-p$

$f≔-n^2+n-p$

$g≔\cos \left(m\right)-q^{-\frac{1}{2}}$

$g≔\cos \left(m\right)-\frac{1}{\sqrt{q}}$

$\mathrm{compose}\left(f\,g\right)$

$-n^2+n-\cos \left(m\right)+\frac{1}{\sqrt{q}}$

$\mathrm{compose}\left(f\,g\,r\right)$

$-n^2+n-\cos \left(m\right)+\frac{1}{\sqrt{r}}$

$\mathrm{compose}\left(f\,g\,n\,r\right)$

$-{\left(\cos \left(m\right)-\frac{1}{\sqrt{r}}\right)}^2+\cos \left(m\right)-\frac{1}{\sqrt{r}}-p$

$\mathrm{compose}\left(f\,g\,n\,m\,r\right)$

$-{\left(\cos \left(r\right)-\frac{1}{\sqrt{q}}\right)}^2+\cos \left(r\right)-\frac{1}{\sqrt{q}}-p$