Important: The group package has been deprecated. Use the superseding command GroupTheory[IsAbelian] instead.

This function determines whether pg is an abelian group. If it is, then true is returned; otherwise false is returned.

The command with(group,isabelian) allows the use of the abbreviated form of this command.

$\mathrm{with}\left(\mathrm{group}\right)\:$

$\mathrm{pg}≔\mathrm{permgroup}\left(8\,\left\{\left[\left[1\,2\right]\right]\,\left[\left[1\,2\,3\,4\,5\,6\,7\,8\right]\right]\right\}\right)\:$

$\mathrm{pg2}≔\mathrm{permgroup}\left(8\,\left\{\left[\left[1\,2\right]\right]\,\left[\left[3\,4\right]\right]\right\}\right)\:$

$\mathrm{isabelian}\left(\mathrm{pg}\right)$

$\mathrm{false}$

$\mathrm{isabelian}\left(\mathrm{pg2}\right)$

$\mathrm{true}$