Important: The linalg package has been deprecated. Use the superseding command LinearAlgebra[HermitianTranspose], instead.

- For information on migrating linalg code to the new packages, see examples/LinearAlgebraMigration.

The Hermitian transpose of A is computed.  The result is an n x m matrix.

The [i, j]th element of the result is equal to the conjugate of the [j, i]th element of A.

The result inherits the indexing (for example, diagonal or sparse) function of A, if A has such an indexing.

If A is a vector, then it is treated as if it were a column (n x 1) matrix.

The command with(linalg,htranspose) allows the use of the abbreviated form of this command.

$\mathrm{with}\left(\mathrm{linalg}\right)\:$

$A≔\mathrm{array}\left(\left[\left[1\,2\right]\,\left[4\,\mathrm{I}\right]\right]\right)$

$A≔\left[\begin{array}{cc}1& 2\\ 4& \mathrm{I}\end{array}\right]$

$\mathrm{htranspose}\left(A\right)$

$\left[\begin{array}{cc}1& 4\\ 2& \mathrm{-I}\end{array}\right]$

$B≔\mathrm{matrix}\left(3\,2\,\left[1+\mathrm{I}\,-3\,-\mathrm{I}\,2\mathrm{I}\,4\,5\right]\right)$

$B≔\left[\begin{array}{cc}1+\mathrm{I}& \mathrm{-3}\\ \mathrm{-I}& 2\mathrm{I}\\ 4& 5\end{array}\right]$

$\mathrm{htranspose}\left(B\right)$

$\left[\begin{array}{ccc}1-\mathrm{I}& \mathrm{I}& 4\\ \mathrm{-3}& -2\mathrm{I}& 5\end{array}\right]$